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10m^2-17m=0
a = 10; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·10·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*10}=\frac{0}{20} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*10}=\frac{34}{20} =1+7/10 $
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